Harold Sakata - Height in feet/cm
How Tall Is Harold Sakata?Harold Sakata height is 5 feet 7.75 inches. Or in metric units - 172 centimetres. |
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Name | Harold Sakata |
Date of birth | July 1, 1920 |
Zodiac sign | Cancer |
Height | 5ft 7.75in (172 cm) |
Gender | Male |
Birthplace | Hawaii, United States |
Country of nationality | United States of America |
Profession | Wrestler, Actor |
Also known as | "Harold Toshiyuki Sakata, Harold Sakata ""Tosh Togo"", Harold ""Odd Job"" Sakata" |
Lists | Wrestler from United States, Wrestler who are 5ft 7.75in (172 cm) |
People of the same height
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