Drew Hankinson - Height in feet/cm

Drew Hankinson

How Tall Is Drew Hankinson?

Drew Hankinson height is 6 feet 7 inches. Or in metric units - 201 centimetres.

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NameDrew Hankinson
Date of birthDecember 22, 1983
Zodiac signCapricorn
Height6ft 7in (201 cm)
GenderMale
BirthplaceMaryland, United States
Country of nationalityUnited States of America
ProfessionWrestler
Also known asFestus, Andrew William Hankinson, Imposter Kane
ListsWrestler from United States, Wrestler who are 6ft 7in (201 cm)

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